(2(cos^2)x)+7sinx+5=0

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Solution for (2(cos^2)x)+7sinx+5=0 equation:


Simplifying
(2(cos2) * x) + 7sinx + 5 = 0

Multiply cos2 * x
(2cos2x) + 7sinx + 5 = 0

Reorder the terms:
5 + (2cos2x) + 7insx = 0

Solving
5 + (2cos2x) + 7insx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-5' to each side of the equation.
5 + (2cos2x) + -5 + 7insx = 0 + -5

Reorder the terms:
5 + -5 + (2cos2x) + 7insx = 0 + -5

Combine like terms: 5 + -5 = 0
0 + (2cos2x) + 7insx = 0 + -5
(2cos2x) + 7insx = 0 + -5

Combine like terms: 0 + -5 = -5
(2cos2x) + 7insx = -5

Add '-7insx' to each side of the equation.
(2cos2x) + 7insx + -7insx = -5 + -7insx

Combine like terms: 7insx + -7insx = 0
(2cos2x) + 0 = -5 + -7insx
(2cos2x) = -5 + -7insx

Divide each side by '(2os2x)'.
c = -2.5o-1s-2x-1 + -3.5ino-1s-1

Simplifying
c = -2.5o-1s-2x-1 + -3.5ino-1s-1

Reorder the terms:
c = -3.5ino-1s-1 + -2.5o-1s-2x-1

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